Synopsis¶
Find the position of the first occurrence of a substring in a string
-
int strpos(string $heystack, mixed $needle, [, mixed $offset=0])
Or
-
strpos
(string haystack, mixed value[, integer offset=0])¶ Parameters: - haystack (string) – String being searched
- needle – String being searched for
- offset (integer) – Search offset from beginning of string
Return type: Position of needle
Description¶
Find the numeric position of the first occurrence of $needle
in the $haystack
string.
Parameters¶
$haystack
- The string to search in.
$needle
- If
$needle
is not a string, it is converted to an integer and applied as the ordinal value of a character. $offset
- If specified, search will start this number of characters counted from the beginning of the string. Unlike strrpos and strripos, the offset cannot be negative.
Return values¶
Returns the position of where the needle exists relative to the beginning of the $haystack
string (independent of offset). Also note that string positions start at 0, and not 1.
Returns FALSE if the needle was not found.
Warning
This function may return Boolean FALSE, but may also return a non-Boolean value which evaluates to FALSE. Please read the section on Booleans for more information. Use the === operator for testing the return value of this function.
Changelog¶
Version | Description |
---|---|
5.2.6 | Something cool happened |
5.2.2 | If the $offset parameter indicates the position of a negative truncation or beyond, false is returned. Other versions get the string from start. |
Examples¶
Using ===¶
Code:
<?php
$mystring = 'abc';
$findme = 'a';
$pos = strpos($mystring, $findme);
// Note our use of ===. Simply == would not work as expected
// because the position of 'a' was the 0th (first) character.
if ($pos === false) {
echo "The string '$findme' was not found in the string '$mystring'";
} else {
echo "The string '$findme' was found in the string '$mystring'";
echo " and exists at position $pos";
}
?>
Using !==¶
Code:
<?php
$mystring = 'abc';
$findme = 'a';
$pos = strpos($mystring, $findme);
// The !== operator can also be used. Using != would not work as expected
// because the position of 'a' is 0. The statement (0 != false) evaluates
// to false.
if ($pos !== false) {
echo "The string '$findme' was found in the string '$mystring'";
echo " and exists at position $pos";
} else {
echo "The string '$findme' was not found in the string '$mystring'";
}
?>
Using an offset¶
Code:
<?php
// We can search for the character, ignoring anything before the offset
$newstring = 'abcdef abcdef';
$pos = strpos($newstring, 'a', 1); // $pos = 7, not 0
?>
Notes¶
Note
This function is binary-safe.